1.
In the following triangle state the cos B.
Solution: Cosine = adjacent/hypotenuse. Therefore cos(B)=4/5.
2.
Determine the measure of ∠V to the nearest tenth of a degree.
Solution: cos(V)=8.9/15.1=0.5894. Therefore V=cos⁻¹(0.5894)=53.9°.
3.
In triangle PQR the cosine of R is:
Solution: Cosine = adjacent/hypotenuse. Therefore cos(R)=PR/QR.
4.
The navigator of a ship at sea sees a lighthouse due north. The ship then sailed 3.2 km due west. The angle between the ship's path and the line of sight to the lighthouse is 39.1°. How far is the ship from the lighthouse to the nearest tenth of a kilometre?
Solution: cos(39.1°)=3.2/x. Therefore x=3.2/0.7771≈4.1 km.
5.
Determine cos A to the nearest tenth.
Solution: cos(A)=adjacent/hypotenuse=16/20=0.8.
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