1.
Use an elimination strategy to solve this linear system: \(20x-24y=-52\) and \(8x+32y=104\).
Choose the correct solution.
Simplify both equations first, then eliminate \(x\) or \(y\). Substitute back to find the other variable.
2.
Create a linear system to model this situation: A length of outdoor lights is formed from strings that are 5 ft long and 11 ft long. Fourteen strings of lights are 106 ft long.
Choose the correct linear system.
Let \(x\) be the number of 5-ft strings and \(y\) be the number of 11-ft strings. One equation counts strings; the other counts total length.
3.
Match each situation to a linear system below. A. Length is 6 m less than double the width. B. Width is one-half the length decreased by 6 m. C. Length decreased by 6 m is double the width. Systems: i) \(2l+2w=163;\ l=2w-6\). ii) \(2l+2w=163;\ w=\frac{1}{2}(l-6)\). iii) \(2l+2w=163;\ 2w=l-6\).
Choose the correct matching.
Translate each phrase carefully: 'less than double' gives \(l=2w-6\); 'one-half the length decreased by 6' gives \(w=\frac{1}{2}(l-6)\).
4.
Use an elimination strategy to solve this linear system: \(\frac{2}{3}m+\frac{3}{4}n=16\) and \(-\frac{1}{2}m+\frac{3}{8}n=18\).
Choose the correct solution.
Clear the fractions by multiplying by the LCD first, then use elimination.
5.
Create a linear system to model this situation: In a board game, Judy scored 3 points more than twice the number of points Ann scored. There was a total of 39 points scored.
Choose the correct linear system.
Translate '3 points more than twice Ann's score' into \(j=2a+3\), then use the total score.
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